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a survey of physicians assistants reported a mean annual income of $84,396 and a standard deviation...

a survey of physicians assistants reported a mean annual income of $84,396 and a standard deviation of 15500. what is the probability that 64 randomly selected physicians assistants will have a mean salary greater than $87500?

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Answer #1

Given, n = 64 Il = 84396 o=15500 The required probability is, P(E>57500) = Pet (2 =plz 87500-u olan plz 87500 - 84396 15500/1

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