Question

10) Physician's Assistants. The population of physician's assistants who were working full time reported a mean annual income of $84,396 and a standard deviation of $21,975. Suppose that instead of calculating data for all physician's assistants, you randomly sample 100 of them. Describe the mean and standard deviation of the sampling distribution of the sample mean. (4 points)

Answer 1

Answer Given data e 84396 deviation Mean standarrd 21975 17 Sample = n : 100 find, mean and standrd deviation of Samp ling di stribution of the that the Sample mean know We In Sampling distribution Samp)e That is, f al the mean means Cx is population Mean (u Sample mean -population mean (u) $84396 Sample mean (X)$8439 ot all Sampl e standard deviation an d the is directly elated the to Saumple mean size. deviation stondard of al The means C) is exacty Sample Vn Lueestandard deviation of sampling distributiorn of sample 21975 +he Mean 2197.5 mean of sampiing distribution of is 8439 Standard deviation of Sampling is $2197.5 Ans Somple mean di stibution of sample mean