The pin is made of a material having a failure shear stress of Ttail 120 MPa...
1.7 LIMIT STATE DESIGN 55 1 F1-22. The pin is made of a material having a failure shear stress of Thail = 100 MPa. Determine the minimum required diameter of the pin to the nearest mm. Apply a factor of safety of F.S. = 2.5 against shear failure. 80 KN F1-22
2. The rod is made of a material having a yield stress oy = 250 MPa. Determine the minimum required diameter for its sections take at segments AB and BC. Apply a factor of safety F.S. = 1.5 against yielding. 600 mm mm 1 ZA 40 KN 50 KN
2. If the solid shaft is made from material having an allowable shear stress of Tallowable = 60 MPa, determine the required diameter of the shaft. 15 kN-m 30 kN m 75 kN-m 30 kN-m QUESTION 5 Problem 2: What is the maximum internal torque in the shaft? 45 kN-m 120 kN-m 25 kN-m 75 kN-m N QUESTION 6 Problem 2: What is the minimum diameter of the solid shaft? O 207 mm O 156 mm O 168 mm 132...
The rods AB and CD are made of steel having a failure tensile stress of O fail = 510 MPa. Using a factor of safety of F.S. = 1.75 for tension, determine their smallest diameter so that they can support the load shown. The beam is assumed to be pin connected at A and C. В. D 6 kN 5 kN 4 kN A C 4 2 m ----2m- -3 m -3 m Figure: 07_PROB_076
scenes M1.1 Normal, shear, and bearing stress For the pin connection shown, Pin diameter = 16 mm determine the normal stress acting on the gross area, the normal stress acting on the net plate area, the shear stress in the pin, and the bearing stress in the 45 kN steel plate at the pin. (Stress units MPa) Pin 70 mm Gusset Steel plate Ogross 10 mm thickness Onet Column T pin Ob
scene 1.1 Normal, shear, and bearing stress For the pin connection shown, determine the normal stress acting on the gross area, the normal stress acting on the net area, the shear stress in the pin, and the bearing stress in the steel plate at the pin. (Stress units = MPa) Pin diameter = 12 mm Gusset plate 25 kN Pin 55 mm Steel plate 6 mm thickness Column Try one 1st 2nd 3 attempt enter t 2001-2017
6. The clevis supports a pin. The attached rod is subjected to a tensile load of 80 kN. If the maximum shear stress the material can support is 20 MPa, determine the required pin diameter to produce a factor of safety of 2.5. (12) 80 kN
Problem 4 (3pts) The beam AB is supported by a single-shear pin connection at joint A and by a double-shear connection to member (1) at joint B. Member (1) is connected to the support at C with a double-shear pin connection. Member (1) has a cross-sectional area of 100 mm and a yield strength of 340 MPa. The pins at A, B, and C each have a diameter of 12 mm, and an ultimate shear strength of 270 MPa. Specifications...
Failure criterion The yield stress of a material is 40 MPa. This material is subjected to the maximum normal stress and the minimum normal stressz--0.350. Determine the magnitude of 01 MPa that will cause yielding according to the maximum shear stress criterion (rounding to two decimal places).
Having issues? See our FAQ Guide QUESTION 1 1. Required Pin Diameter for a Frame The frame shown supports a mass of 500 kg. Determine the diameter of the pin in [mm] at joint A for a factor of safety of 3. Assume fat allowable shear stress for the pin is 150 MPa and that the joint is a single shear type. 2m + 2m А С B 2 m ID 500 kg 2 m E