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The rods AB and CD are made of steel having a failure tensile stress of O...
The cotter is used to hold the two rods together.(Figure 1) All parts are made of steel for which the failure normal st...
The cotter is used to hold the two rods together.(Figure 1) All
parts are made of steel for which the failure normal stress is
?fail=525 MPa and the failure shear stress is
?fail=325 MPa. Use a factor of safety of
(F.S.)t=2.90 in tension and(F.S.)s=1.70 in
shear.
Determine the smallest thickness t of the cotter.
Determine the smallest diameter d of the rods.
Part A The cotter is used to hold the two rods together. (Figure 1) All parts...
Part A The cotter is used to hold the two rods together. (Figure 1) All parts are made of steel for which the failure normal stress is fail = 510 MPa and the failure shear stress is Trail = 365 MPa. Use a factor of safety of (F.S.)t = 2.30 in tension and (F.S.), = 1.71 in shear. Determine the smallest thickness t of the cotter. Express your answer to three significant figures and include appropriate units. de = Value...
A temporary support steel frame (E 200 GPa) is made of 30-mm diameter solid circular steel rods (members AB and CD), an...
A temporary support steel frame (E 200 GPa) is made of 30-mm diameter solid circular steel rods (members AB and CD), and 22-mm diameter solid circular steel rods (members BC and AD), al pin connected at the turnbuckle corners A, B, C, and D (see Figure below). The steel frame is braced by two cables AC and BD. A turnbuckle is fitted to cable AC and tightening it will induce tension 3m in cable AC. Determine the largest allowable tension...
The assembly shown in the figure below consists of solid AB, BC and CD rods connected...
The assembly shown in the figure below consists of solid AB, BC and CD rods connected together, the solid rod AB has 10 mm diameter and 100 mm length, the solid rod BC has 20 mm diameter a 120 mm length, while the solid rod CD has 10 mm diameter and 100 mm length. Allh rods are made of steel with E-200 GPa. the assembly is subjected to 100 kN tensile force (CLO5) The average normal stress between A and...
The 5m beam is supported by a pin in double shear at Cand cable AB. The...
The 5m beam is supported by a pin in double shear at Cand cable AB. The cable has a tension of 40.7 kN and is subjected to the point loads shown. Design a pin diameter at C to the closest mm so that it will not fail under shear stress. Use a yield shear stress of 160 MPa and a F.S. against yield of 2. 3.7KN PPKN 14.8KN 74 KW .5 1.5m 1,5m 40.7KN A CS Scanned With CamScanner- O...
Two identical steel rods AB and CD each have a length L = 6 m and...
Two identical steel rods AB and CD each have a length L = 6 m and cross-sectional areas of 500 mm2, and are used to support the rigid beam, which is pinned at A and maintains an initial gap of 0.2 mm to support F. If a vertical force P is applied at the end of the beam, (i) (ii) determine the value of P required to close the gap If P = 12 kN, determine the force in rod...
1.41 Link AB is to be made of a steel for which the ultimate normal stress...
1.41 Link AB is to be made of a steel for which the ultimate normal stress is 450 MPa. Determine the cross-sectional area of AB for which the factor of safety will be 3.50. Assume that the link will be adequately reinforced around the pins at A and B. 8 kN/m 35° C 20 kN 0.4 m 0.4 m 0.4 m Fig. P1.41
1.41 Link AB is to be made of a steel for which the ultimate normal stress is...
The pin is made of a material having a failure shear stress of Ttail 120 MPa...
The pin is made of a material having a failure shear stress of Ttail 120 MPa Part A Determine the minimum required diameter of the pin to the nearest mm. Apply a factor of safety of FS 2.5 against shear failure. 80 KN Tap image to zoom Express your answer as an integer and include the appropriate units d= Value ! Units SubmitRequest Answer
Determine the smallest thickness t of the cotter Express your answer to three significant figures and...
Determine the smallest thickness t of the cotter Express your answer to three significant figures and include appropriate units The cotter is used to hold the two rods together (Figure 1) All parts are made of steel for which the failure normal stress is σ1il 520 MPa and the failure shear stress is Tail385 MPa. Use a factor of safey of (F.S.), 2.10 in tension and (F.S.) 1.71 in shear d,-Value Units Figure 1 of 1 SubmitR Request Answer 30...
1.7 LIMIT STATE DESIGN 55 1 F1-22. The pin is made of a material having a...
1.7 LIMIT STATE DESIGN 55 1 F1-22. The pin is made of a material having a failure shear stress of Thail = 100 MPa. Determine the minimum required diameter of the pin to the nearest mm. Apply a factor of safety of F.S. = 2.5 against shear failure. 80 KN F1-22
The cotter is used to hold the two rods together.(Figure 1) All
parts are made of steel for which the failure normal stress is
?fail=525 MPa and the failure shear stress is
?fail=325 MPa. Use a factor of safety of
(F.S.)t=2.90 in tension and(F.S.)s=1.70 in
shear.
Determine the smallest thickness t of the cotter.
Determine the smallest diameter d of the rods.
Part A The cotter is used to hold the two rods together. (Figure 1) All parts are made of steel for which the failure normal stress is fail = 510 MPa and the failure shear stress is Trail = 365 MPa. Use a factor of safety of (F.S.)t = 2.30 in tension and (F.S.), = 1.71 in shear. Determine the smallest thickness t of the cotter. Express your answer to three significant figures and include appropriate units. de = Value...
A temporary support steel frame (E 200 GPa) is made of 30-mm diameter solid circular steel rods (members AB and CD), and 22-mm diameter solid circular steel rods (members BC and AD), al pin connected at the turnbuckle corners A, B, C, and D (see Figure below). The steel frame is braced by two cables AC and BD. A turnbuckle is fitted to cable AC and tightening it will induce tension 3m in cable AC. Determine the largest allowable tension...
The assembly shown in the figure below consists of solid AB, BC and CD rods connected together, the solid rod AB has 10 mm diameter and 100 mm length, the solid rod BC has 20 mm diameter a 120 mm length, while the solid rod CD has 10 mm diameter and 100 mm length. Allh rods are made of steel with E-200 GPa. the assembly is subjected to 100 kN tensile force (CLO5) The average normal stress between A and...
The 5m beam is supported by a pin in double shear at Cand cable AB. The cable has a tension of 40.7 kN and is subjected to the point loads shown. Design a pin diameter at C to the closest mm so that it will not fail under shear stress. Use a yield shear stress of 160 MPa and a F.S. against yield of 2. 3.7KN PPKN 14.8KN 74 KW .5 1.5m 1,5m 40.7KN A CS Scanned With CamScanner- O...
Two identical steel rods AB and CD each have a length L = 6 m and cross-sectional areas of 500 mm2, and are used to support the rigid beam, which is pinned at A and maintains an initial gap of 0.2 mm to support F. If a vertical force P is applied at the end of the beam, (i) (ii) determine the value of P required to close the gap If P = 12 kN, determine the force in rod...
1.41 Link AB is to be made of a steel for which the ultimate normal stress is 450 MPa. Determine the cross-sectional area of AB for which the factor of safety will be 3.50. Assume that the link will be adequately reinforced around the pins at A and B. 8 kN/m 35° C 20 kN 0.4 m 0.4 m 0.4 m Fig. P1.41
1.41 Link AB is to be made of a steel for which the ultimate normal stress is...
The pin is made of a material having a failure shear stress of Ttail 120 MPa Part A Determine the minimum required diameter of the pin to the nearest mm. Apply a factor of safety of FS 2.5 against shear failure. 80 KN Tap image to zoom Express your answer as an integer and include the appropriate units d= Value ! Units SubmitRequest Answer
Determine the smallest thickness t of the cotter Express your answer to three significant figures and include appropriate units The cotter is used to hold the two rods together (Figure 1) All parts are made of steel for which the failure normal stress is σ1il 520 MPa and the failure shear stress is Tail385 MPa. Use a factor of safey of (F.S.), 2.10 in tension and (F.S.) 1.71 in shear d,-Value Units Figure 1 of 1 SubmitR Request Answer 30...
1.7 LIMIT STATE DESIGN 55 1 F1-22. The pin is made of a material having a failure shear stress of Thail = 100 MPa. Determine the minimum required diameter of the pin to the nearest mm. Apply a factor of safety of F.S. = 2.5 against shear failure. 80 KN F1-22
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