1) work done = change in kinetic energy
Work done = 50 - 0.5m(Vf²)
Work done = 50 - 0
Work done = 50 J
An electron with a kinetic energy equal to 40 J is moving in an electric field....
An electron with a kinetic energy equal to 40 J is moving in an electric field. The electric field produces a force the slow the electron to a stop. How much work in Joules is done on the electron? Enter only the numerical value. Submit response An electron with 50 J of energy enters a magnetic field. The magnetic field changes the direction of the electron to follow a helical path, but keeps a constant speed. How much work in...
Moving Proton in an Electric Field Part A A proton with kinetic energy of 1.02x105 eV is fired perpendicular to the face of a large plate that has a uniform charge density ofơ-+4.40 C/m2, what is the magnitude of the force on the proton? Submit Answer Tries 0/6 Part B How much work must the electric field do on the proton to bring it to rest? Submit Answer Tries 0/6 Part C From what distance should the proton be fired...
Use conservation of energy please!! An electron is initially at ground level, and the electric potential at that point is assumed to be exactly zero. The electron is immersed in a uniform electric field that points down with a magnitude of 4.4 x 10-11 N/C as well as Earth's gravitational field (9.8 N/kg, pointing down). Only gravity and the electric force have any effect in this problem. a) If the electron is given an initial upward velocity of 36 m/s,...
Which field can change the kinetic energy of an electron? a. an electric field. b. a magnetic field c. both of them. d. neither. Which field can accelerate an electron, but not change its kinetic energy? a. an electric field. b. a magnetic field c. both of them. d. neither.
An electron acquires 7.90×10−16 J of kinetic energy when it is accelerated by an electric field from plate A to plate B.
An electron acquires 5.85×10−16 J of kinetic energy when it is accelerated by an electric field from plate A to plate B. What is the potential difference between the plates?
An electron with kinetic energy 228 eV is moving in a horizontal direction. The electron moves into a region where there is a uniform vertical electric field which has magnitude 3990 N/C. Find the smallest magnitude of a magnetic field that will cause the electron to continue to move horizontally. (1eV=1.6^10^(-19)J;mass of the electron=9.11*10^(-31)kg)
1. An electron travels through an electric field. The kinetic energy of the electron changes from 4.00 x 10-18 J to 3.95 x 10-18 J. Determine: a) the change in kinetic energy of the electron, b) the fall in electrical potential (voltage). c) its total energy (EPE + EC), at any point in its trajectory. (Remember the energy is conserved.) (EPEinitial = 0.00 J)
9. An electron moving with non-relativistic velocity v in an electric field E experiences a magnetic fieldB given by: v x (-V(r)) v x E B=- where (r) is the electric potential. This magnetic field interacts with the magnetic moment u of the electron given by -S, =n me where S is the electron spin. Assuming non-relativistic mechanics, show that the Hamiltonian representing this effect (spin-orbit coupling) for a spherically-symmetric electric potential is: 1 dφ(r) S.L ΔΗ [6] r dr...
An electron acquires 6.90×10-16 J of kinetic energy when it is accelerated by an electric field from plate A to plate B. What is the potential difference between the plates? = _________________ V Which plate is at the higher potential?