Be careful to keep a lot of significant figures for all of your answers!
R1 = 2 Ω R2 = 6 Ω R3 = 13 Ω R4 = 8 Ω V = 4 V
1) What is the current through the resistor, R1in the above circuit?
I =
2) What single, equivalent resistor could replace all of the resistors in this circuit?
Rtot =
3)
3) What is the current supplied by the battery?
I =
4) What is the current through the resistor, R2?
I =
R2 and R4 are in parallel
1/6+1/8= 14/48
R' = 48/14= 3.428ohm
R' and R1 are in series R"=2+3.428= 5.428ohm
R" AND R3 ARE IN PARALLEL
1/Req= 1/13 +1/5.428
Req= 2.7126ohm
Current supplied by battery = 4÷2.7126= 1.4746A
Current through R1 and R'
V=4V
4/5.428= 0.7369A
V across R2 is 0.7369 ×3.428= 2.526V
Current through R2
2.526/6= 0.421A
Be careful to keep a lot of significant figures for all of your answers! R1 =...
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