Question

Consider the electric circuit shown in the figure. Assume that the voltage of the battery is V = 23.5 V, and the resistors are R₁ = R₂ = R₃ = R₄ = R₅ = 2.00 Ω.

What is the equivalent resistance of the circuit?

What is the electric current flowing through resistor R₃?

Consider the electri = R4 = R5 = 2.00 2 circuit shown in the figure. Assume that the voltage of the battery is V = 23.5 V, and the resistors are R1 = R2 = R3 R3 What is the equivalent resistance of the circuit? Submit Answer Tries 0/12 What is the electric current flowing through resistor R3? Submit Answer Tries 0/12 Send Feedback Post Discussion

Answer 1

(i) R_2 and R_5 in series R_s = R_2 + R_5 = 2 + 2 = 4 ohm 4 ohm, 2 ohm in parallel R_p = 4 times 2/4 + 2 = 8/6 ohm R_p = 1.333 ohm Now 2 ohm, 1.333 ohm, 2 ohm are in series therefore R_eq = 2 + 1.333 + 2 R_eq = 5.333 ohm I = V/R_eq = 23.5/5.333 = 4.406 A \r\n (ii) Voltage across R_1 is = IR_1 = (4.406)2 = 8.812 v Voltage across R_4 is = IR_4 = (4.406)2 = 8.812 v voltage across R_3 and R_2 + R_5 are same because they are parallel. Voltage across R_3 = 23.5 - 8.812 - 8.812 V_R_3 = 5.876 v current across R_3 is V_R_3/R_3 = 5.876/2 I_R_3 = 2.938 A