From the stoichiometry of the reaction
1 mol I2 produced from = 2 moles of NaI
253.81 g I2 produced from = 2*149.89 = 299.78 g of NaI
67.4 g I2 produced from = 299.78*67.4/253.81
= 79.61 g of NaI
php?id 4954882 TBOOK 17 of 24 How many grams of sodium iodide, Nal, must be used...
How many grams of sodium iodide must be used to produce 68.9 g iodine? STRATEGY 1. Convert the mass of 1, to moles. 2. Convert the number of moles of I, to the number of moles of Nal 3. Convert the number of moles of Nal to grams Step 1: Convert 68,9 g iodine, L2 - to moles. 68.9 g iodine = mol
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Assignment Score: 48% Resources Hint Check Answer Question 13 of 27 > lodine is prepared both in the laboratory and commercially by adding Cl(s) to an aqueous solution containing sodium iodide. 2 Nal(aq) + Cl, (g) 1,(s) + 2 NaCl(aq) How many grams of sodium iodide, Nal, must be used to produce 28.2 g of iodine, 1,7 mass: Nal Q MOC Published by
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