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18. Suppose $6,000 is invested in an account at an annual interest rate of 4.5% compounded...
18. Suppose $2,900 is invested in an account at an annual interest rate of 6.6% compounded...
18. Suppose $2,900 is invested in an account at an annual interest rate of 6.6% compounded continuously. How long (to the nearest tenth of a year) will it take the investment to double in size? Answer: 19. Let f(x) = x2 - 10x + 18. (a) Find the vertex. Answer: (b) State the range of the function. Answer: (c) On what interval is the function decreasing? Answer:
Suppose $8000 is invested at 7% interest compounded continuously. How long will it take for the...
Suppose $8000 is invested at 7% interest compounded continuously. How long will it take for the investment to grow to $16000? Use the model A(t) = Pe" and round your answer to the nearest hundredth of a year. It will take years for the investment to reach $16000.
Suppose $20,000 is invested in an account that returns 9% per year compounded continuously. (Round your...
Suppose $20,000 is invested in an account that returns 9% per year compounded continuously. (Round your answers to one decimal place.) (a) How long will it take for the investment to double? yr (b) How long will it take for the investment to triple? yr
Suppose that Po is invested in a savings account in which interest is compounded continuously at ...
Suppose that Po is invested in a savings account in which interest is compounded continuously at 59% per year. That is, the balance P grows at the rate given by the following equation dP 0.059P(t) dt (a)Find the function P(t) that satisfies the equation. Write it in terms of Po and 0.059. (b)Suppose that $1500 is invested. What is the balance after 2 years? (c)When will an investment of $1500 double itself? (a) Choose the correct answer below. Po P(t)...
If you invest $6,000 today in an account at an annual interest rate of 7% compounded...
If you invest $6,000 today in an account at an annual interest rate of 7% compounded continuously, what would you have in the account at the end of 6 years? DO NOT USE DOLLAR SIGNS OR COMMAS IN YOUR ANSWER. ROUND ANSWER TO THE NEAREST CENT (2 Decimals). LIST THE NUMBER AS A POSITIVE NUMBER.
If $3500 is invested in an account earning 11% annual interest compounded continuously, then the number...
If $3500 is invested in an account earning 11% annual interest compounded continuously, then the number of years that it takes for the amount to grow to $7000 is In 2 0.11 Find the number of years The approximate number of years for the amount to grow to $7000 is years. (Do not round until the final answer. Then round to the nearest tenth as needed.)
In the year 2003, $1700 was invested in an account that pays interest at a 2%...
In the year 2003, $1700 was invested in an account that pays interest at a 2% annual rate, compounded continuously. Let A (t) be the amount of money, in dollars, in the account at time t, where t = 0 corresponds to the year 2003. Write a formula for A (t) A(t) = 1700(1.02) A(t) = 1700(2) none of these A(t) = 1700(e) 0.02 A (t) = 1700 + 2+ In the year 2003, $1700 was invested in an account...
8. $1000 is invested in a saving account with an annual interest rate 4%. Find the...
8. $1000 is invested in a saving account with an annual interest rate 4%. Find the balance of the account after 15 years in the following situations (round each answer to its nearest 100th): (i) The interest is compounded annually. (ii) The interest is compounded monthly. (iii) The interest is compounded continuously.
will give thumbs up Suppose that P dollars in principal is invested for years at the...
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Suppose that P dollars in principal is invested for years at the given interest rates with continuous compounding. Determine the amount that the investment is worth at the end of the given time period. P = $8000, t = 13 yr a. 2% interest b. 4% interest c. 4.5% interest Part 1 out of 3 a. At a 2% interest rate, the investment will be worth $ at the end of 13 yr. 2Use the model...
Use the model A Peor A-P1+ where is the future value of dollars invested at interest...
Use the model A Peor A-P1+ where is the future value of dollars invested at interest rater compounded continuously or times per year for years. If $14,000 is invested in an account earning 7.5% interest compounded continuously, determine how long it will take the money to double. Round up to the nearest year. It will take approximately 9.3 years.
18. Suppose $2,900 is invested in an account at an annual interest rate of 6.6% compounded continuously. How long (to the nearest tenth of a year) will it take the investment to double in size? Answer: 19. Let f(x) = x2 - 10x + 18. (a) Find the vertex. Answer: (b) State the range of the function. Answer: (c) On what interval is the function decreasing? Answer:
Suppose $8000 is invested at 7% interest compounded continuously. How long will it take for the investment to grow to $16000? Use the model A(t) = Pe" and round your answer to the nearest hundredth of a year. It will take years for the investment to reach $16000.
Suppose that Po is invested in a savings account in which interest is compounded continuously at 59% per year. That is, the balance P grows at the rate given by the following equation dP 0.059P(t) dt (a)Find the function P(t) that satisfies the equation. Write it in terms of Po and 0.059. (b)Suppose that $1500 is invested. What is the balance after 2 years? (c)When will an investment of $1500 double itself? (a) Choose the correct answer below. Po P(t)...
If $3500 is invested in an account earning 11% annual interest compounded continuously, then the number of years that it takes for the amount to grow to $7000 is In 2 0.11 Find the number of years The approximate number of years for the amount to grow to $7000 is years. (Do not round until the final answer. Then round to the nearest tenth as needed.)
In the year 2003, $1700 was invested in an account that pays interest at a 2% annual rate, compounded continuously. Let A (t) be the amount of money, in dollars, in the account at time t, where t = 0 corresponds to the year 2003. Write a formula for A (t) A(t) = 1700(1.02) A(t) = 1700(2) none of these A(t) = 1700(e) 0.02 A (t) = 1700 + 2+ In the year 2003, $1700 was invested in an account...
8. $1000 is invested in a saving account with an annual interest rate 4%. Find the balance of the account after 15 years in the following situations (round each answer to its nearest 100th): (i) The interest is compounded annually. (ii) The interest is compounded monthly. (iii) The interest is compounded continuously.
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Suppose that P dollars in principal is invested for years at the given interest rates with continuous compounding. Determine the amount that the investment is worth at the end of the given time period. P = $8000, t = 13 yr a. 2% interest b. 4% interest c. 4.5% interest Part 1 out of 3 a. At a 2% interest rate, the investment will be worth $ at the end of 13 yr. 2Use the model...
Use the model A Peor A-P1+ where is the future value of dollars invested at interest rater compounded continuously or times per year for years. If $14,000 is invested in an account earning 7.5% interest compounded continuously, determine how long it will take the money to double. Round up to the nearest year. It will take approximately 9.3 years.
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