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Suppose that Po is invested in a savings account in which interest is compounded continuously at ...
Suppose that is invested in a savings account in which interest, k, is compounded continuously at...
Suppose that is invested in a savings account in which interest, k, is compounded continuously at 3% per year. The balance P(t) after time t, in years, is P(t) = Pekt a) What is the exponential growth function in terms of P and 0.03? P(t)=0
An amount of $1500 is invested at an interest rate of 7.8 % compounded continuously. What...
An amount of $1500 is invested at an interest rate of 7.8 % compounded continuously. What will the final value of this investment be after 30 years? The correct formula to calculate the final value is O A. P=1500 e -(0.078)(30) OB. P= 1500(1 +0.078,30 OC. P = 1500(1 +0.078) - 30 OD. P=1500 e (0.078(30) O E. None of the above The investment will be worth $ after 30 years. (Round to the nearest cent as needed.)
Suppose $6,600 is invested at interest rate k, compounded continuously, and grows to $10,600 in 6...
Suppose $6,600 is invested at interest rate k, compounded continuously, and grows to $10,600 in 6 years. a) Find the interest rate. b) Find the exponential growth function. c) Find the balance after 10 years.
5) Suppose $6,600 is invested at interest rate k, compounded continuously, and grows to $10,600 in...
5) Suppose $6,600 is invested at interest rate k, compounded continuously, and grows to $10,600 in 6 years. a) Find the interest rate. b) Find the exponential growth function. c) Find the balance after 10 years.
a. $4,200 is invested with a 5.2 % APR compounded continuously. What is the value of...
a. $4,200 is invested with a 5.2 % APR compounded continuously. What is the value of the investment after 13 years? Preview b. $700 is invested with a 3.5% APR compounded continuously. What is the value of the investment after 13 years? Preview c. $2,100 is invested with a 4.6% APR compounded continuously. What is the value of the investment after 13 years? Preview Submit Question 1. Points possible: 3 Unlimited attempts. Message instructor about this question Post this question...
Complete the table for a savings account in which interest is compounded continuously. (Round your answers...
Complete the table for a savings account in which interest is compounded continuously. (Round your answers to four decimal places.) Initial Annual Time to Amount After Investment % Rate Double 14 Years $250 $335.21
Suppose $20,000 is invested in an account that returns 9% per year compounded continuously. (Round your...
Suppose $20,000 is invested in an account that returns 9% per year compounded continuously. (Round your answers to one decimal place.) (a) How long will it take for the investment to double? yr (b) How long will it take for the investment to triple? yr
Suppose $8000 is invested at 7% interest compounded continuously. How long will it take for the...
Suppose $8000 is invested at 7% interest compounded continuously. How long will it take for the investment to grow to $16000? Use the model A(t) = Pe" and round your answer to the nearest hundredth of a year. It will take years for the investment to reach $16000.
18. Suppose $6,000 is invested in an account at an annual interest rate of 4.5% compounded...
18. Suppose $6,000 is invested in an account at an annual interest rate of 4.5% compounded continuously. How long (to the nearest tenth of a year) will it take the investment to double in Answer size?
Suppose that $16,416 is invested at an interest rate of 5.5% per year, compounded continuously. a)...
Suppose that $16,416 is invested at an interest rate of 5.5% per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time t, in years. b) What is the balance after 1 year? 2 years? 5 years? 10 years? c) What is the doubling time? a) The exponential growth function is P(t) = (Type exponential notation with positive exponents. Do not simplify. Use integers or decimals for any
Suppose that is invested in a savings account in which interest, k, is compounded continuously at 3% per year. The balance P(t) after time t, in years, is P(t) = Pekt a) What is the exponential growth function in terms of P and 0.03? P(t)=0
An amount of $1500 is invested at an interest rate of 7.8 % compounded continuously. What will the final value of this investment be after 30 years? The correct formula to calculate the final value is O A. P=1500 e -(0.078)(30) OB. P= 1500(1 +0.078,30 OC. P = 1500(1 +0.078) - 30 OD. P=1500 e (0.078(30) O E. None of the above The investment will be worth $ after 30 years. (Round to the nearest cent as needed.)
Suppose $6,600 is invested at interest rate k, compounded continuously, and grows to $10,600 in 6 years. a) Find the interest rate. b) Find the exponential growth function. c) Find the balance after 10 years.
5) Suppose $6,600 is invested at interest rate k, compounded continuously, and grows to $10,600 in 6 years. a) Find the interest rate. b) Find the exponential growth function. c) Find the balance after 10 years.
a. $4,200 is invested with a 5.2 % APR compounded continuously. What is the value of the investment after 13 years? Preview b. $700 is invested with a 3.5% APR compounded continuously. What is the value of the investment after 13 years? Preview c. $2,100 is invested with a 4.6% APR compounded continuously. What is the value of the investment after 13 years? Preview Submit Question 1. Points possible: 3 Unlimited attempts. Message instructor about this question Post this question...
Complete the table for a savings account in which interest is compounded continuously. (Round your answers to four decimal places.) Initial Annual Time to Amount After Investment % Rate Double 14 Years $250 $335.21
Suppose $8000 is invested at 7% interest compounded continuously. How long will it take for the investment to grow to $16000? Use the model A(t) = Pe" and round your answer to the nearest hundredth of a year. It will take years for the investment to reach $16000.
18. Suppose $6,000 is invested in an account at an annual interest rate of 4.5% compounded continuously. How long (to the nearest tenth of a year) will it take the investment to double in Answer size?
Suppose that $16,416 is invested at an interest rate of 5.5% per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time t, in years. b) What is the balance after 1 year? 2 years? 5 years? 10 years? c) What is the doubling time? a) The exponential growth function is P(t) = (Type exponential notation with positive exponents. Do not simplify. Use integers or decimals for any
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