Question

Example 6.8 Figure 6.12 shows the one-line diagram of a simple three-bus power system with generators at buses 1 and 3. The m use causs-sedel method (programing by matlap) for seven iteration please answer step by step and show me the results in workspace for this system:-
0.02 +0.04 400 MW 0.01 + 30.03 0.0125+ 20.025 250 Mvar Slack Bus Vi = 1.0520° 200 ( 1 V3 = 1.04 MWplease answer for seven iteration using matlap .
V.= 0.97073 - 30.04479 Q P = 1.42904 V S = 0.97065 – 30.04533 Q= 1.44833 V, 6) = 0.97062 – 20.04555 095) = 1.45621 v (6) = 0.these represented some answer for system which are solution of example with out matlap please prove that in matlap
220 6. POWER FLOW ANALYSIS 179.362 170-9682 218.423 (8.393) (16.787) 118.734 101.947 101.947 O 39.061 146.352 | 38.878 (58) 2power flow for example
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Answer #1

Solution Power flow solution for the network using N-R method 427 = 16-332 0.02 + 30.04 42 = 10.320 h 400mw 14,3=102530 1 0.0and the the exp for real powed at bus 2 and 3 reactive power at bus a are Per luz 11. Ilya,l.cos( 021-82 +,] + vž) 14:21 COSdQ2 - lus 11vs11423Cos (023 - $2+83) 253 əlvel 1Q2 =- Villyzil Sin (021-82 +81)-2 lVallY22 | Sin (022) - TV3 11423] Sin 023-8OG() 2-0,0452 82%)= 0+(-0.0452) = -0,04526 A530) -0.007218 $3)= 0+(-0.00718) = -0.007718 Alv,lo) )= -0,02654 Juilla 1+(-0.Q3= - IUS II vill Ysıl fin ( 031-83+ -1) - 1 V3 1102 11 4321. Sin (032- 83 +52) – 1V3 ? 11433 1 Sin D32 3119u1cos 1692-8,+62)

answered by: ANURANJAN SARSAM
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Answer #2

Solution Power flow solution for the network using N-R method 427 = 16-332 0.02 + 30.04 42 = 10.320 h 400mw 14,3=102530 1 0.0and the the exp for real powed at bus 2 and 3 reactive power at bus a are Per luz 11. Ilya,l.cos( 021-82 +,] + vž) 14:21 COSdQ2 - lus 11vs11423Cos (023 - $2+83) 253 əlvel 1Q2 =- Villyzil Sin (021-82 +81)-2 lVallY22 | Sin (022) - TV3 11423] Sin 023-8OG() 2-0,0452 82%)= 0+(-0.0452) = -0,04526 A530) -0.007218 $3)= 0+(-0.00718) = -0.007718 Alv,lo) )= -0,02654 Juilla 1+(-0.Q3= - IUS II vill Ysıl fin ( 031-83+ -1) - 1 V3 1102 11 4321. Sin (032- 83 +52) – 1V3 ? 11433 1 Sin D32 3119u1cos 1692-8,+62)

answered by: ANURANJAN SARSAM
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