Question

A rigid container with a volume of 10 cubic meters contains are at 5 degrees C with a relative humidity of 100%, a pressure of 1 bar, and 0.25kg of liquid water at 5 degrees C. If the container is heated until the mixture reaches a temperature of 80 degrees C, determine the final pressure and relative humidity of mixture. Also, determine the percent of the volume of the container occupied by the liquid at the initial condition, and discuss if it is important in the problem.

Answer 1

Answer:

Given that,

V = 10 m ³

Relative humidity = 100%

Pressure 1 bar

- weight transaction of water at Ti Rut = 100%, P = Iban = 0.005966 kg/ng of dry ais. - Density Pw of water at 50 =999.92.5. kg/m3. =) volume of water = vw = 20 22058104 m3 by the =) Percent of volume of the container occupied liquid at the initial condition 1001 2-58104 10 -0.0025% -> Initial density of air, Pa =p 287X288 = 1.21 kg/m3 Mass of. auch, ma. Pax(v-vw) = 1.21 % (10 – 0.0025) = 1.21kg 1 m3 Masgotation

=> constant volume pececess for air ideal gas equation Total of .CPU P2) P2 = Pix Tz X 2+3+80 27375 = 2698 bea - internal energy Relative humidity = PHRO Pout 100 =-) At 5%, Post 0.00872575 badi = PH₂O 2) Dory cier pressure, Pi-Pitzo a Pia 1-0.00872595 = 0.9512792.5 bar. Boy after pressure, Pla -1.2587 bour PHO = (-2698 - »2587 -0.01109 bar At soc. Psont = 0 and this bar

u RH = PH2O x 100% Psat = 2.34% Initial liquid volume percent helps to evaluate volume occupied by. aia and then mass of the us.