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Calculate the integral accurate to within 0.001 (use Maclauren series) 0.1 2-6x2 dx.

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EX Given e dx mclaurin series or e is We know that x O! e x 1! + + + --- Ž 2! n! n=0 Replace fx with :-62- e-6x2 (-6X) + (-6*Here, if we take Absolute value of 0.00036 0.000036 10 So take the series as, 0.1 -6x² dx = 0.006 0.00 3 0.1-0.002 0.098 j 0-

answered by: ANURANJAN SARSAM
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Calculate the integral accurate to within 0.001 (use Maclauren series) 0.1 2-6x2 dx.
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