Q1
N2F2 --> planar since no lone pairs left to reppeal
H2NNH2 --> not planar, since Nitrogen has lone pairs which reppeal each bond, therefore, 3-D structure
NCCN --> planar, mainly because of the triple bond formed by Carbon
Q2
delocalized electrons
must have at least double bonds so PI electrons are present
N2F2 --> not likely
H2NNH2 --> no electrons in ¨PI
HCCN --> linear, thereofre not possible
choose "none"
Q1 N2F2 planar because there are no lone pairs left to repel
H2NNH2 not planar it is a 3-D structure
NCCN planar and has a triple bond
Q2
N2F2 does not
H2nnh2 does not
HCCN is the correct answer because although it wouldn't appear to have delocalized pi bonds it is possible to draw a resonance structure moving pi electrons away from their original location.
Answer was confirmed correct through Smartwork5 itself.
Best of luck!
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