Question

Assuming the heterocyclic ring above to be planar:

Give the number of electrons that are contributed to the pi system of the heterocyclic ring by: 

How many electrons are in the pi system of the heterocyclic ring? (In the case of fused rings add all the pi electrons.) 

Is the heterocyclic ring with the numbered atoms aromatic?

Answer 1

→ B H H Boazine is an inorganic compound with which is isoelectronie and isostructural with Benzene. So also referred as inorganic Benzene Electronic configuration of B: Boron atom is 18², 28² 26² two electoons shoot 3-valence shell electrons of completing Electronic configura tron of Ni its octet- 182, 28, 2p. Hence, Noatom donates its lone 5-valence electrons. Pairs to adjacent B-atom's empty p-cobrtals.) (Boron И H B B Н. N-H -H B H 8 H-B. -H H- H - 2 9 No. of electrons contributed by atoms towards 1- System: atom 1 (N-atom) 2 elections Clone paid) atom 2 CB-atom) o electron atom 3 CH-atom) o electron No. of elections in n-system! Each N-atom contributes 2 electrons towards T-cloud Hence, 2x 3 = 6 electrons which is in accordance with the [4n+2] Huckele's Rule for aromatics. Hence, an aromatic compound. yes, Borazine is an aromatic compound. As it is planes and follows [40+2) a electrons sule in a cyclic conjugated system. 3