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AND FREE ENERGY pr entropy For each Chemical reaction listed in the first column of the table below, predict the sign (positi
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Answer #1

For the reaction 2SO3(g) ---> 2SO2(g) + O2(g)

                       2 moles          2 + 1 = 3 moles

The number of moles of products are more than that of reactants so entropy increases there by \Deltarxn > 0

For the reaction N3(g) +3H2(g) ---> 2NH3(g)

                       1+3=4 moles          2 moles

The number of moles of products are less than that of reactants so entropy decreases there by \Deltarxn < 0

For the reaction NaCl(s) ---> Na+(aq) + Cl-(aq)          

The products which are in aqueous state and the reactant is in solid state so entropy increases there by \Deltarxn > 0


answered by: ANURANJAN SARSAM
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