Question

2 MV. What volume of a 0.175 M KOH solution is needed to neutralize 50.0 mL of 0.0875 MHNO,? M=0.875M HNO, +KOH → KNO, +H,0 M₂ = 0.175m MV = Va V = 50ml (0.975)) (50mL) My 2 TO. MEN V = 250 mL KOH

I would like to see if you get the same answer as me. I saw a different answer from another tutor on here and figured it was wrong. They got 25mL HNO3

Answer 1

HNO3 + KOH KNO3 + H2O we know that . (V - 12V, Mi.= molarity of Hus = 0.0875M M = volume of HNG = 50 ML Me= rolarity of Kolt= .0.1759 ve = volume of Koh = ami rivi Mr 0:0875 X 50 0.175 = 25ML volume of Kol (Ve) = $15ML