Question

Two points, A and B, are terminal ends of a line-segment (place horizontally). Point X is above the line a distance 23- cm away from point A (nearer to A than B). Point Z is above the line a distance 12-cm away from point B (nearer to B than A). The point T is below the line. As such, there are line segments XT and ZT each of which crosses the line segment AB. The distance from point X to the point where XT intersects AB is 12-cm. The distance from point Z to the point where ZT intersects AB is 5-cm. Let a = ZZBA, and y LXTZ. Additionally, the angles at ZXAB, B points X and Z are right angles. First, draw a clearly labeled picture of this scenario Second, convince yourself that y = a B. Third, and finally, find tany Preview License Points possible: 10 Unlimited attempts.

Answer 1

naux Bleu ? Jung 12cu O P Given ĂX =23 uy, B2= 12 cm LXAB = LZ BA=90 Let c be and be the intersection point of AB with XT and ZT respectively X = 1204, D2=5cm Given. 9 ААХС LACX : 180-(LXAC + LAXC) -180-190 +a)= 90-a similarly in ABDZ - [BD2 = 90-ß In A CDT ITCD=LACK T opposite angle] ITDC = LBD2 r opposite angle] LCĪD = 180 - (LTC D+L TDC) - 180-(go-d +90-ß) = 180-180 + atß = a +ß - tand laup +18= atp taiso taula tp) = tana + tauß tand- 12 from & AXT] taup- & grouBD ] 2+ taura Scanned with CamScanner 144+115 - 259 12 12/23-5 216 Itaur=1.2 + 25