Question

In an L-R-C series circuit, R = 260 ?, L = 0.820 H, and C= 0.0230 ?F. The source has voltage amplitude V = 150 V and a frequency equal to the resonance frequency of the circuit (a) What is the power factor? (b) What is the average power delivered by the source? (c) The capacitor is replaced by one with C = 0.0460 ?F and the source frequency is adjusted to the new resonance value. Then what is the average power delivered by the source?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

v J L-0.8 20H fre quency 61 Sou ce Reso mnt frequent Equivalert Impedloma at vesonante condition .eu Thc Note: is argle powveraosr delivered b he Source ts at resononh eondition the Impedone shot cơ cui ed .. Total Volhage will be acsov Teui to ..

Add a comment
Know the answer?
Add Answer to:
In an L-R-C series circuit, R = 260 ?, L = 0.820 H, and C= 0.0230...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • In a series R-L-C circuit, L = 0.215 H , C = 82.5 μF and the...

    In a series R-L-C circuit, L = 0.215 H , C = 82.5 μF and the voltage amplitude of the source is 260 V . 1)What is the resonance angular frequency of the circuit? 2)When the source operates at the resonance angular frequency, the current amplitude in the circuit is 0.595 A . What is the resistance R of the resistor? 3)At the resonance frequency, what are the peak voltages across the inductor, the capacitor, and the resistor?

  • In a series R-L-C circuit, R = 380 Ω , L = 0.330 H and C...

    In a series R-L-C circuit, R = 380 Ω , L = 0.330 H and C = 1.10×10−2μF . Part A What is the resonance angular frequency of the circuit? Part B The capacitor can withstand a peak voltage of 550 V . If the voltage source operates at the resonance frequency, what maximum voltage amplitude can it have if the maximum capacitor voltage is not exceeded?

  • In a series R-L-C circuit, L = 0.190 H , C = 84.5 μF and the...

    In a series R-L-C circuit, L = 0.190 H , C = 84.5 μF and the voltage amplitude of the source is 290 V . Part A What is the resonance angular frequency of the circuit? ω0 =   rad/s   SubmitMy AnswersGive Up Part B When the source operates at the resonance angular frequency, the current amplitude in the circuit is 0.610 A . What is the resistance R of the resistor? R =   Ω   SubmitMy AnswersGive Up Part C At...

  • Constants In a series R-L-C circuit, R = 480.2 L = 0.370 H and C =...

    Constants In a series R-L-C circuit, R = 480.2 L = 0.370 H and C = 1.50x10-2uF Part A What is the resonance angular frequency of the circuit? ΟΙ ΑΣΦ ? p = 13801 rad/s Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Part B The capacitor can withstand a peak voltage of 550 V. If the voltage source operates at the resonance frequency, what maximum voltage amplitude can it have if the maximum capacitor voltage...

  • Exercise 31.29 In an L-R-C series circuit, 310 ,0.396 H and 5.98x10-8F. When the ac source...

    Exercise 31.29 In an L-R-C series circuit, 310 ,0.396 H and 5.98x10-8F. When the ac source operates at the resonance frequency of the circuit, the current amplitude is 0.505 A. Part A What is the voltage amplitude of the source ? ANSWER: V V Part B What is the amplitude of the voltage across the resistor? ANSWER: V Part 6 What is the amplitude of the voltage across the inductor? ANSWER: Vi V Part D What is the amplitude of...

  • Question 12 (1 point) In an L-R-C series circuit, L = 0.253 H, and C =...

    Question 12 (1 point) In an L-R-C series circuit, L = 0.253 H, and C = 4.02 ?F. The voltage amplitude of the source is 130 V. What is the resonance angular frequency of the circuit in rad/s?

  • 6) In an L-R-C series circuit L = 0.440 H, R 380.0 n, and C-5.70μF. The...

    6) In an L-R-C series circuit L = 0.440 H, R 380.0 n, and C-5.70μF. The 6) voltage amplitude of the source is 250.0 V. Find the rms voltage across the capacitor when the source operates at resonance

  • Resonance in an R-L-C Circuit In an L-R-C series circuit, the resistance is 320 ohms, the...

    Resonance in an R-L-C Circuit In an L-R-C series circuit, the resistance is 320 ohms, the inductance is 0.300 henrys, and the capacitance is 1.80x102 microfarads. Part A What is the resonance angular frequency wo of the circuit? Express your answer in radians per second to three significant figures. Vie Available Hint(s) 1.29 10 rad/s wo Previous Answers Submit x Incorrect; Try Again; 5 attempts remaining Part B The capacitor can withstand a peak voltage of 560 volts. If the...

  • An L-R-C series circuit L = 0.124 H , R = 245 Ω , and C...

    An L-R-C series circuit L = 0.124 H , R = 245 Ω , and C = 7.28 μF carries an rms current of 0.451 A with a frequency of 394 Hz A)What is the phase angle?' F)What is the average rate at which electrical energy is dissipated (converted to other forms) in the capacitor?    B)What is the power factor for this circuit? G)in the inductor? C)What is the impedance of the circuit? D)What is the rms voltage of...

  • In an L-R-C series circuit, the resistance is 380 ohms, the inductance is 0.360 henrys, and...

    In an L-R-C series circuit, the resistance is 380 ohms, the inductance is 0.360 henrys, and the capacitance is 1.40×10−2 microfarads. 1)What is the resonance angular frequency ω0 of the circuit? 2)The capacitor can withstand a peak voltage of 580 volts. If the voltage source operates at the resonance frequency, what maximum voltage amplitude Vmax can the source have if the maximum capacitor voltage is not exceeded?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT