(III) is least unstable base because it is more basic so fastly abstract the proton from acid source.
And (I) is most stable base because it is very less basic than other so it is not easily abstract the protons from acid source.
Hence correct answer is c).
Arrange the following weak bases in order of expected increasing stability. H CH CH3 H-C-H HC-N-CH,...
help?
Arrange the following weak bases in order of expected increasing stability. Η Ο H' H-C d! : - H-C-0-0 H-0- H I II a. (least stable base) III < II < I (most stable base) b. (least stable base) II < III < I (most stable base) c. (least stable base) I < II < III (most stable base) d. (least stable base) III < I < II (most stable base) e. (least stable base) I < III <...
Arrange the following weak bases in order of expected increasing stability. Η Ο HH H-C-0- H-0-0- H-0- H I Η Η II III a. (least stable base) II < I < III (most stable base) b. (least stable base) I < III < II (most stable base) c. (least stable base) I < II < III (most stable base) d. (least stable base) II IIII (most stable base) e. (least stable base) III <I < II (most stable base) f....
Rank the following carbocations in order of increasing stability. CH-C1 CH; C -CH-CT o C -CH3 CH-Cl CH; ܚ II INI a. (least stable) II < III < I (most stable) b. (least stable) I III < II (most stable) c. (least stable) III < II < 1 (most stable) d. (least stable) III III (most stable) e (least stable) I II III (most stable) (cast stable) III III (most stable) Arrange the following weak bases in order of expected...
2. Arrange the following in order of: (i) increasing reactivity with HCI. CH, CH CH H.C=C nec nec 20 cm H.C=C CH HC=C CH, (b) H.C=C NHCH, CHOCH, ОСН, (a) (c) (d) Teast reactive most reactive (ii) increasing stability. CH CH3 CH (a) (C) least stable most stable (iii) increasing heat of hydrogenation. CH,CH, CH=CH2 C H.CH O CH.CH CH3 CH,CH; CH,CH, (0) lowest heat of hydrogenation
Please explain your reasoning for the correct answer
also
Arrange the following in order of increasing stability CH2CH3 CH3 CH CH CH CH,CH, most stable least stable.
Arrange the following in order of increasing stability CH2CH3 CH3 CH CH CH CH,CH, most stable least stable.
Rank the following carbocations in order of increasing stability. CHCI CH -CHCI C–CH CH C1 CH I II III a. (least stable) I < II < III (most stable) b. (least stable) II < I < III (most stable) c. (least stable) III < I < II (most stable) d. (least stable) III < II < I (most stable) e. (least stable) I < III < II (most stable) f. (least stable) II < III < I (most stable)
( 4 ) Arrange the following carbocations in the order of increasing stability (least stable first). СНа OC-CHE H-C-H N - a) IV, I, III, II b) III, I, IV, !! c) III, IV, II, 1 d) I, II, II, I
Arrange the following Newman projections in order of increasing stability (least stable first). H3C CH3 CH3 CH3 HC CH CYCH н кX CXн Х TH CHE сн. CH3 o B,D,A.C o D, B, A, C O A, B, D, C o C, B, D, A What is the structure of intermediate 1? BD, HC THA CHA CHA Product Nou H2O, NaOH |
Arrange the following radicals in order of increasing stability
(least stable to most stable)
Arrange the following radicals in order of increasing stability (least stable to most stable). Least stable Most stable
Arrange the following three bases in order of increasing base strength. NH CH3OH ОСН; II I III a. (Weakest base) I < II < III (Strongest base) b. (Weakest base) I < III < II (Strongest base) c. (Weakest base) II < I < III (Strongest base) d. (Weakest base) II < III < I (Strongest base) e. (Weakest base) III < II <I (Strongest base) f. (Weakest base) III < I< II (Strongest base)