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232) How many loads of gravel are needed to cover 5 mi of roadbed, 56 ft...

232) How many loads of gravel are needed to cover 5 mi of roadbed, 56 ft wide,
        to a depth of  8 in. if one truckload capacity is  8 yd^3?
        5280 feet = 1 mile.  


234) (H) A gasoline engine has four cylinders, each with a bore of 52 mm
        and a piston stroke of 68 mm.  Find the engine displacement in
        liters and in^3. 2.54cm=1inch. 1Liter=1000cm^3  
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Answer #1

SSiven Itiat rat s the sand bed= 5mi 5గ =264004t NRde =56ft depth=0tn SX0.03383=o-Eee44t elme st g Seuguied= 26400 x56 X0.6 6Selbricyivnen that No.o cylinda4 B8tela 52mm 5-2Cm pisten stuok ee 62mm 6.80m Displacanent T*2pX x(5.x (6-8) 144.41 Cm = 1444

answered by: ANURANJAN SARSAM
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