Question 1:
In detail and show and explain all steps
Digital Electronics
Answer
Question 1
area of 32-bit word
= 32*2μm by 4μm
= 64μm by 4μm
we see that the length is 16 time height....ie (24 : 1) ratio of length to height
therefore for square layout format we must have 24 rows for 1 word in a row
so in order to layout 212 words in square format
if there are 2N words in a row we must have 2N+4 rows in square format
total words in this format = (no.of words in a row)*(No of rows) = 2N x 2N+4 = 22N+4 = 212
= 2N+4 = 12
= N = 4
therefore there are 24 = 16 words in a row
and there are 24+4 = 28 = 256 rows
the area of the SRAM is (64*16μm) by (4*256μm)
= 1024μm by 1024μm
for 2N outputs of a decoder there are N inputs
therefore
for column decoder
there are 24 outputs of decoder
hence 4 inputs
for row decoder
there are 28 outputs of decoder
hence 8 inputs
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