Question

A parking garage has 5 customers daily. The garage charges a $5.00 minimum fee to park up to two hours. The garage charges an additional $1.00 per hour for each hour (or part of an hour) over two hours. The maximum charge for any given day is $12.00. All cars are gone by midnight. Write a program to calculate and print a summary of the charges for a day. For input the program will read the hours of usage for each of the 5 cars. The program will print the results in the form of a table in a neat format, as shown below.

Enter the hours parked for car 1: 1.5

Enter the hours parked for car 2: 4.1

Enter the hours parked for car 3: 12.0

Enter the hours parked for car 4: 9.3

Enter the hours parked for car 5: 0.5

Total Hours 27.4       

Total Charge $42.00

Use one decimal place for the hours parked, and 2 for the total charge. Name this program ParkingGarage.cpp

Answer 1

Answer:

Note: the calculation of the charge is a detail, and instead of giving $ 44.4 in question gives 42.0 $.

Solution:

file ParkingGarage.cpp

#include <stdio.h>
#include <stdlib.h>

int main(){
float garage_charge=5.0, garage_charge_additional=1.0, garage_charge_maximum=12.0; //variables
float cars[5], total_hours, total_charge;
  
total_hours = total_charge = 0.0; // initials values
  
// read data for cars
for (int i=0; i<5; i++){
while (true){
printf("Enter the hours parked for car %d: ",i+1);
scanf("%f", &cars[i]);
if (cars[i]>12.0)
printf("Enter value no more than 12 hours");
else
break;
}
}

for (int i=0; i<5; i++){
if (cars[i]<=2.0){ // if hours is <= 2.0 then the rate is $ 5.00
total_charge += garage_charge;
}else{ // but will be $ 5.00 more the calculation of the additional hour for each hour
total_charge += garage_charge + ((cars[i]-2.0)*garage_charge_additional);
}
  
total_hours += cars[i]; // calculate the total hours
}
  
// print results
printf("\n\nTotal Hours %.2f\n", total_hours);
printf("Total Charge $%.2f\n\n",total_charge);
  
system("pause");
return 0;
}

output: