Question

You may want to review (Pages 768-771).

Part A

What is the magnitude of the current in the 11 Ω resistor in (Figure 1) ?

Part B

What is the direction of the current in the 11 Ω resistor in (Figure 1)?

Answer 1

a)

using ohm's law

i = (E1 + E2) / R

i = ( 6 + 3) / 11 = 0.8182 A

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b)

option (a) is correct

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Comment before rate in case any doubt, will reply for sure .. goodluck

Answer 2

SOLUTION :

a.

Voltage across resistor of 11 Ω

 = sum of emf of battery 1 and battery 2 

= 3 + 6 = 9 V

So, current in the circuit = 9/11 = 0. 8182 amps. (ANSWER)

b.

Direction of current is from left to right through the resistor.  (ANSWER).