Question

Q1:- Find the time period of the fluid in a U-tube manometer shown by using Newton Method. Fluid density e Tube area A KA

Answer 1

A=Tube cross-section Selution Fluid density I Mean Rise Depressed position L ZT h he height of liquid at equilibrium position ak B m let us it in in vxt Mass of liquid = Axan xe Neglecting 2 AMP the mase of AB part Assumption Assume that very less part the left u turn limb is depressed by amount ½ in vertically downward The difference of level of liquid in two limb liquid in •F=-kn-ng li

On the Right line extra liquid rice Above equilibrium position Act a Restoring force on the liquid F = of liquid Above equilibsium position F = img PAX ex mass F = - g But by the Mewton second have F and 11 -PA lxg 2 Ah x pa= -P Alxg lg sh =; ( 2 ) x 1 - } - This particle is in SHM

gi • By the Time period of SHM Ta za tra T- 26 112 From Bii To lux