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Answer #1

P = 120 W ; R = 20 ohms

part A

P = V2/R

or, emf = V =sqrt (RP) = 48.99 Volts

part B

V = IR

or, I = emf /R = 48.99/20 = 2.45 A

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A battery supplies 120 W with a 20 omega resistor across its terminals. Part A Find...
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