Question

In the figure ε1 = 2.73 V, ε2 = 1.22 V, R1 = 7.36 Ω, R2 = 2.67 Ω, R3 = 5.83 Ω, and both batteries are ideal. What is the rate at which energy is dissipated in (a) R1, (b) R2, and (c) R3? What is the power of (d) battery 1 and (e) battery 2?

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Answer #1

RS 0 uo applying nodal anelyais at bint す 2 2.73-v-4 于36 122-v-ㄧㄧˇ- 2.67 5.83 Solui 2.73214 3.3 o059 A 2. 67 R31214 D:2082 5now that we have calculated current in each resistors,

Power is

I^{2} R

So in

R1= 0.31202w

R2=1.348*10^{-5} W

R3= 0.2527 W

And power from battery is

EI

So in battery 1

P=2.73*0.2059

=0.562107W

From battery 2

P=1.22*2.247*10^{-3}

2.74134*10^{-3}W

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