Question

b) [3 points] What will be the output of the following code? Explain your answer. enum direction {UP, DOWN, LEFT, RIGHT); void foo (enum direction* a, enum direction b) enum direction * c = a; b = RIGHT; *c = LEFT; *c = RIGHT ; int main (void) enum direction d1 = enum direction d2 printf ( "d1 %d, d2 foo (&d1, d2); printf("d1- %d, d2 return 0 UP; DOWN; = %d\n", d1, d2); %d\n", d1, d2);

Answer 1

d1 is passed as reference, So changing value with in the function reflects in main.
d2 is passed as value, so changing value with in the function does not reflects in main.

In foo function:
----------------
c is referencing a.
and changing the value of a using reference c with the line "*c = LEFT".
Then reassigning c with b.
But changing the value of b does not reflects in main.

So, after the function call
value of a is LEFT and value of b is DOWN.

So, Output is
d1 = 0, d2 = 1
d1 = 2, d2 = 1

Note: enums starts with 0.