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1. Assign the point group to each of the following molecules below by identifying all of the mirror planes, inversion centers
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a) MCl2Br2 is C2V

Plane of symmetry: Plane passing through Cl-M-Cl and Plane passing through Br-M-Br. (two plane of symmetry)

Cn axis: C2 axis passing through angle bisector of Cl-M-Cl and another through angle bisector of Br-M-Br (two axis)

b) XeF4 is D4h

Plane of symmetry:

Plane passing through all five atoms.

plane passing through opposite F atoms

plane passing through angle bisector of F-Xe-F bonds.

Centre of symmetry: Xe is centre of symmetry

Cn axis: C4 axis passing through Xe and perpendicular to all Xe-F bonds

C2 axis passing through angle bisector of F-Xe-F and in plane of all atoms.

C) SF4 is C2V

Plane of symmetry: passing through F-S-F bond (Fs are not adjecent)

Symmetry axis: Passing through sulfur (S) and lying along lone par of S

D) it is D3h

Plane: Passing through Fe and three CO groups

another Passing through each F-CO bond and perpendicular to the other plane

Axis: one passing through Cl-Fe-Cl bond and other three axis passing through each F-CO bond.

E) it is C2V

Plane : Passing through Cl-Fe-Cl; anther passing through Three CO and Fe

Axis: passing through angle bisector of Cl-Fe-Cl

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