Question

Process the following three stations through AM superheterodyne receiver under two cases assuming that you are tuning to station 1. Show the signal arrangements in frequency domain. Case 1: No RF filter Case 2: RF filter added with BW=400 kHz Sma Smi - - -- LANky 575 53° 585 605 613 615 -610 -500 1m3 . Нt 1985 149 1495 - 1490

Answer 1

Given that the three stations through AM Supershet erodyne under two cases 15m3 ismi - Sm2 | 1495 575 580 585 1485 1490 Kit KH? Le 605 610 615 - -1490 KHR R -50 - 610 - 610 Given these stations are at diffre eut frequencies of tuning. Case is : No RF filtre 1. turning to station 1. because there are smo, sm2, sm3 ale is the same range, these stations have different ranges, given th the R mbare sm) -580 Frree Bandwidth (BW) range of some of 10 k Ha So low bandanda Stations will turn Compane high bandwidth stations it we have not Consider the Rf helter then low bandladth of stations I will tun Compare to high baudulidth stations of sma quod 5m3, and here sma, sma are not range at smo Case is RF filter added with BW=400k Ha at station I and stations a will turn and station 3 will not turn with RF filter :- colded with BW= 400k Ha station I and station 2 are in the lange of super heterodyne Receiver of RF filter with added 400 kHR 5m2 sm3 ismi -580 KHz 15m2 580 -610 210 Кна 1 Sma smi: 580 + 200 k H2 = 380 k H2, 780 K Ha smy: 610 + 200 kHz = 410 KHz, 810 K Ha Stay : 1490 + 200 k H2 = 1290 kHz, 1690 KHz the station sm, and sma are in the range of RF filter added with BW = 400 K Hz but sm3 not in the range so sm, and smg will tuum.