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Using as few steps as possible, show how you cloud Provide each step and reagents
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Answer #1

1)

i)Presence of weak acetic acid make conditions slightly acid. Under slightly acidic conditions carbonyl O get protonated. H2O abstract proton from ? position and carbanion generated get stabilized in polarized C=O bond.

ii) Reversal electron density on ?- C cause nucleophilic attack at polarized Br-Br bond and 2-Bromocyclohexanone formation takes place. (AcOH has main role as Br-Br bond polarizer)

iii)Then a bulky non-nucleophilic base t-BuO- cause ?- elimination reaction and forms Cyclohex-2-enone.

iv) Ph2CuLi (Gilman reagent) undergo exclusively conjugate addition across enone and if we supplied reaction with methyl iodide (Me-I) at the same time then second addition at ? position also takes in same reaction and formation of final product takes place.

Br )Ph2CuLi (Gilman Me H2O/AcOH reagent) r2 Il) Me-l Ph 2-Bromo- cyclohexanone Cyclohexanone Cyclohex-2-enone 2-Methyl-3-phen

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2)

i) SeO2 (selenium dioxide) is selective oxidizing agent which oxidizes ? position in carbonyl compounds to oxo (C=O group). Cylohexanone on treatment with SeO2 forms cyclohexane-1,2-dione.

ii)Cyclohexane-1,2-dione on treatment with 1 equivalent of phosphorus Ylide forms C=C bond on reaction one of the C=O group. This reaction is known as Wittig reaction.

iii)Anathor C=O group on reaction with Grignard reagent PhMgBr and on subsequent acid hydrolysis will give the required product.

Ph OH CH 2 CH2 Wittig reaction CH2-PPh3 PhMgBr/ether i)H3Oe SeO2 a-oxidationPRosphorus ylied2methylene2-methyene-1-phenyic yc

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3)

i)Base Lithium diisopropyl amide (LDA) generates carbanion which on treatment with 3-Bromoethannitrile shows SN2 reaction and forms required product.

3-bromopropanenitrile CN CN LDA SN2 cyclohexanone 3-(2-oxocyclohexyl)propanenitrile

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