Question

5. The titrations using 1.31 x 10-M NaOH was performed and were consumed 7.17 mL of base, how many moles of acid were in the sample?

Answer 1

2 2 cuven- concentration (molarity of NaOH = 1:31 X100m : 0.131 m volume of Nash used = 7.17 ml = 0.007174 Jo, moles of Moore used : molarity X volume lin ) : 0.131 X 0.00717 : 0.0009393 moles = 9.393 X10-4 moles sf acid used is monopronic I.p. HA type (ex. HCI O HI Hype), then moles of acid in sample will be 9.393x10" moles, as per following reaction - maoni + HCl + Naul + H2O Imole Naos – requires i mole HU So. 9.393 X10Y mole wool requires 9.393 Xro-Ymote Hal If acid used as diprofic ine. Hy A type (Ex-H2 504), then moles of acid in the sample will be 9.393 810-4_4.696 X 10-4 as per following reaction & NAOH + MgSO4 + Nggsou +2430 2 mole Naon - requires i mole Masou I mole Nooh - requires mole Ho sou So 9.393x1004 Noon — requires **9.393 x10-4 mole Mason o similarly if it is polyprofic acid of type HnA then number of moles of acid = 99.393 X10~Y moles. e mole = 4.696 x 10-4 mole