Question

03.0 Compute the torque on an object when a 13N force acting perpendicular at a distance of 6 km. A car has a mass of 5010 kg. If the locomotive can exert a constant pull of 9000 N, compute the time it takes to increase the speed of the train from rest to 32 m/s. A car traveling at a constant speed passes a police car. Two seconds after the speeding car passes the police car, the police started to chase it with acceleration of 14 m/s. The police reached the speeding car after 40s, estimate the constant speed of the car.

Answer 1

Forme F-130 perpendicular; distance - 6km - 6x103m. We know, torque a Porreex perpendiculat distance Это го - 13X6X103 ps 7.8x109 Nomi The tosque on an object is 7.8x10 N.m. (1) мая лh m = 501 от Initial velnity uso Final velocity &- 32 aufree. Applied formee & - 900ON. we know, Newton's and law. Pornce & Massx acceleration F = mx e-u 9000 = 5010X 3200 2) t = 50108.32 gom It 2 17.85 seel The required time to increase speed is 17.81 see.

zle (11) het, the constant streed of cadeis. Initial velocity of police cade is zo Acceleration of police care is a - lauf Time t=40see. The Distance travell by speeding care after sosee is So vx40 as =400 - The distrace travell by police care after 4ogee is sont that = 207 3x 144402 - S= 7X16 = 21200 m. The the value of s putting in een we get, sagore 2 = 11200 ſe = 280m/s The constant speed of speeding care is 280 msee. Ao