Can anyone help me with this? Assume the entire graph of f(x) is shown below. Ø...
For the given graph of f(x) below, use interval notation to express the solution to f(x) > 0. -7-675-- -2 -1 A) (0,0) B) (-5,2) u (5, 9) c) (0,3) D) (-00,-5) u (2,5)
The graph of f(x) is shown. At which of the point(s) is f '(x) >0 and f "(x) < 0? List all points where both f '(x) > 0 and f '(x) <0. If there is only one point where this is true, list it. If there is more than one point, list them all and separate the answers by commas. If there is no such point, type N.
please answer all 3 of them I paid $6 lol :( Question 22 (1 point) Graph the function. S x4, -{ f(x) = -x2, if x > 0 if x < 0 A) OB) OC) OD) Question 24 (1 point) The function chown in the graph can best be represented by which function? piecewise-defined function 10 -10 8 6 .4 2 2 46 8 10 4 -8 10 ºr(a)= {**2*, *20 º r(t) = {* *2* *.50 flx S (x...
Find the specified area. The area under the graph off over the interval [-2.4 f(x)= 5. if x < 1, 5x?. if x 21 448 OA. I OB. 120 OC, 330 OD 30
Sketch the graph that possesses the characteristics listed below. f'(3) = 0,1" (3) <0, f(3) = 5; f'(-1)= 0, f'(-1)>0, f(-1)= -1;f" (1) = 0, f(1) = 2 Choose the correct graph below. OA. OB O C. OD. 10
Find all values x= a where the function is discontinuous. 7 if x <4 f(x) = x- 9 if 4 sxs7 7 if x>7 O A. a=7 O B. a=9 OC. a=4 OD. Nowhere
Integrate the function. - dx, x<2 De 10, x2 om (2nd OB. a 1703 12 +0 oc. (4-2) ?. Oo. (1-2) 112* 12y3 3 / 2 + ) 1/2
If a quantity y satisfies the differential equation dy = kx(10-y), k>0 dx. when X = 2 and y = -7, the graph of yir increasing decreasing constant cannot be determined
The graph of y(x) is shown to the right. Identily the intervals on which f'(x) <0. Which of the following shows every interval on which f(x) <0? Choose the correct answer below. O A. (b,d), (g) C. (a,b). (c.e). (g) O B. (a,b). (ce) O D. (a,b), (c,d), (g) Click to select your answer
2. Draw a possible graph of the function described: (6 pts.) 10 O 00 07 f(-3)=4, f (2)=0 f'(-4)= f'(2) = f'(9)=0) f'>0 when x < -4 and x > 2 f' <0 when - 4<x<2 f">0 when -1<x< 5 or 9<x<10 f" <0 when x < -1 or 5<x< 9 or x >10 4 N NH -10 -8 -6 -4 -2 -2 4 07 8 10 -4 -6 -8 -10