For the given graph of f(x) below, use interval notation to express the solution to f(x)...
Solve the inequality. Express your answer using set notation or interval notation. Graph the solution set. - 5(3x-6) < - 30 Choose the correct answer below that is the solution set to the inequality. O A. {X/X> 4) or (4,00) OB. {X/X <4) or (-0,4) O C. {XIX > 4) or (4.00) OD. {X/X <-4} or (-0,-4) Choose the correct graph below that is the solution set to the inequality. OA OB -6 6 9 -9 -6 -3 0 3...
Question 6 Solve: (write solution set in interval notation) x-1 x-2 x-x-2 a) <1 b) > 0 X-5
5 points) 1. Circle the correct answer. Use the graph of y = f(x) to solve f(x) < 0. A) (-2, 0) U (3,00) TVfx) B) (-2,0] [3,00) C) (-00, 2] U [0,3] D) (-00,-2) (0,3) E) none of the above
(1 point) If f(x) = { 6x, x39 8 x >9 Evaluate the integral 10 6.". f(x) dx |
6 Points Let F be the vector field represented in the figure: P(-1,1) 1907/1X X Q3.1 3 Points O2d-Curl F(0,0) > 0 O2d-Curl F(0,0) = 0 O2d-Curl F(0,0) < 0 Q3.2 3 Points OV.F(0,0) > 0 OV.F(0,0) = 0 OV.F(0,0) < 0
Suppose that f is integrable on (a, b) and define (f(x) if f(x) > 0 f+(x) = 3 and f (2)= if f(x) < 0, Show that f+ and f- are integrable on (a, b), and If(x) if f(x) > 0, if f(x) < 0. cb Sisleyde = [* p*(e) ds + [°r(a)di. | f(x) dx = | f+(x) dx + 1 f (x) dx.
12 if x = 1,2 1. Define f:[0,2] → R by the rule f(x) = { 11 otherwise a. For any e > 0, find a partition Psuch that U (f, Pc) < € (be careful, as the minimum value for the function is one and not zero) b. Evaluate ſf
Exercise 6. Show that if f(x) > 0 for all x e [a, b] and f is integrable, then Sfdx > 0.
4- Find f'(x) if f(x) is the given expressions. i) f (x ) = zsin ">" + ln cosh - 4x ii) f(x) = tanh-- 4x etanh4x
1. Given the piece-wise function, 3x if x < 0 f(x)=x+1 if 0 < x 52 :- 2)2 if x>2 Evaluate f (__); f(0); f (); f(5)