Question

1. A multiple friction clutch is required to transmit 89.52 kW at 3000 rpm. The plates are alternatively of steel and phosphor bronze and they run in oil. The coefficient of friction is 0.08. The internal radius of the friction surface is 0.8 times the radius of the external surface. The axial pressure is limited to 20 x 104 N/m2. If the maximum diameter of the frictional surface is not to exceed 250 mm, determine the number of plates required.

Answer 1

DO Page Lo given, Power 89.52 kW N = 3000 rfem D = 250mm , u: 0.08 E =0.8 or d 2 0.8 dl=0.8 x 250 - 2.00mn R Pa= 20x10 N/m2 = 0.2N/mm² → As there is no specific mention of which theory to use we will be solving the problem assuming Tuniform wear theory" Stef-s Calculate Torque Transmitted. - P= TW Р - Ту отм T= PX60 2AN. Steb-2 = 89.52X 1000 x 60 2x ax 3000, T= 284.95N-m = 28495 IN-mm Calculation of force ?" P= Pad CD-d. 2 - 3.14% 0.28 200 x (250-200) - 3141.59N

tive is Date Page Step 3 - Calculating Required no of dieks. - Ta upa ord) z = 4T - lux P CD & d) = 4X(284950 0.08 x 3141:59 x(250+ 200) = 10.07 ñ 10 z z ks will be z tl ie 10+1 = 11 , we will use 6 Steel & 5 phosphor Brome elales