Question

(1) Consider a double pane system of glass which reflects 0 < p <1 percent of the total incident light on each pane and transmits (1 – p) through. (Assume this is not dependent on incidence angle.) Answer the following questions. (a) If light with intensity 1 hits the first pane how much will pass through? How much will be reflected? (b) After the light passes through first pane it travels through the air between the panes before hitting the second pane. Given that the second pane also refracts p of the percent how much is passes through the second pane of the original light? (c) The light that reflected off the second pane now bounces back towards the first pane. If it reflects off the first pane again then it will go towards the second pane and may pass through. What amount of the original light passes through the second pane on it second second interaction? (d) What amount of the original light passes through on the third interaction? (e) Using series find the total amount of incident light that passes through both panes.

I know that you are only supposed to answer three parts but it would be amazing if you could help me with the entire problem

Thank you so much!

Answer 1

a double pane . I'o- we have system each pone , reflects = transmits = 1-p (a) for first pone amount of light pass = 1-p amount of light reflected = & amount of light pass a Ab (1-0) from second pane = amount of ught in betw EU-b) x (1 -b) = (1-P) 2 -

(0) App (r Þ. reflection from 2nd pane = plit again, reflection from foot Pane = (1-P) p² transmission on and pane on and interaction = (1-P) [u-te pe ] = (1-P) 2 82 . Similarly for of third of this interaction on second fone = (helt fa fa ug = (-+{ P* [0=P 49] = (1 -b) ? $4 - T Similarly done, as did above)

( For light to pass at fourth interac- -tion = (1+[p? (520-D BI] = (+? ÞO -@ from ☺ ☺ ☺ and 2 , 9 Total with p amount of incident light which pass = 11-B)2 + (1-P) 282 + $(1-2 + 11-62 pot =11-79**1 + ? ++4 +5 + --) The sum of series 1 + $2 + $9+pot - (1-59 - (: Sn = 1/2) for arul

from and , = (1-12 x 1 (1-22) mount of light pass = (1-P) (1-P2)