Given:
n = 13, p = 0.5
q = 1-p = 1-0.5 = 0.5
Requirement for a normal approximation for the Binomial distribution:
np =13*0.5= 6.5
nq =13*0.5=6.5
Both np and nq are greater than 5.
So Condition satisfied.
Find: P(at least 8)
P(at least 8) = P(X =8) + P(X =9) + P(X =10) + P(X =11) + P(X =12) + P(X =13)
Therefore, the probability mass function of the binomial distribution is as follows:
.............................X = 0,1,2,3.........................n
Therefore,
P(at least 8) = 0.1571 + 0.0873 +0.0349+0.0095 + 0.0016 + 0.0001
P(at least 8) = 0.291
ANSWER: A
P(at least 8) = 0.291
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