Question

. Below is a graph of the change in volume of propane as a function of temperature. Does the graph depict a relationship predicted by Charles's Law?

Temperature (K) o o o o ot oo ost Volume (ml)

4. A gas occupies a volume 31.0 L at 19.0 ^oC. If the temperature rises to 38.0 ^oC, what would the new volume be?

5. A balloon is inflated with helium to a volume of 0.82 L at 26 ^oC. Several hours later, the balloon was found, and the temperature had dropped to 21 ^oC. What would the volume of the balloon be when found?

Answer 1

Ti T2 Answer:- Charles' law - This law states that the volume of a fixe of a gas is directly proportional to the temperature. " is applied to the ideal gases at Censtant presswie. V = V2 [from the graph; yes, the graph depict a relationship predicted by L ' Chaule's law. V = 31.0L Cinitial volume) Ti = 19°C = 273+ 19 =292 K ( Initial temperature) v₂ = ? (new or final volume) Tz = 38°C = 38+273 = 311k (Final temperature) Substitute the values in equation 0 ; . 31€ = 1₂ Here, 2928 311k V2 = 34. x 311 = 334 Vz= 332 . The new volume would be 334 Angwer © Vi = 0.82 L (Initial volume) T = 26°C = 26+ 273 = 299K V2 = ? ( Fional volume) : T2 = 21c - 21+273 = 294k Substitute the values in equation ® , we geti 0.82 L 2 V₂ 299 K 294 K Vg = 0.82 x 294 20.8062 L 0.814 Vs = 0.811] The volume (V₂) of the balloon at zic is 0.8L. V2 299