how many grams of H2O can be formed from the reaction of 7.0 g of
2-propanol?
The balanced equation for the combustion of propanol is as follows,
2C3H8O + 9O2 --> 6CO2 + 8H2O
Given,
Mass of Propanol = 7 g
Molar Mass of Propanol = 60.09 g / mol
=> Moles of Propanol = 7 / 60.09 = 0.1165 moles
According to the stoichiometry of the reaction, 2 moles of Propanol produces 8 moles of water
=> Moles of water produced by reaction of 0.1165 moles of Propanol = 0.1165 x 4 = 0.466 moles
Molar Mass of water = 18 g / mol
=> Mass of water produced = 0.466 x 18 = 8.39 g
how many grams of H2O can be formed from the reaction of 7.0 g of 2-propanol?
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