Question

7. If a woman who is red-green colorblind (sex linked!) mates with a man with normal vision, what phenotypes would one expect their children to have? Practice Genetic Problems a) all their children would be color blind; b) all their daughters will be color-blind, but all their sons will have normal vision. c) all their daughters will be carriers and all their sons will be color-blind. d) all their daughters will have normal vision and will not be carriers, but all their sons will be color blind. e) half their daughters will be carriers and the other half will be fully normal; half their sons will be color-blind and the other half will have normal vision. 8. If a child has AB blood type, the parents: a) must both have different blood types; b) must be A and B but not AB; c) must both be AB; d) can be any blood type, but must be different; e) can both be AB or must be different and neither can be type 0. 9. Two individuals that are heterozygous for A and B blood types respectively have children. Which of the following are possible blood types of their children? a) A b) B; c) AB; d) O; e) all of these are possible. 10. Ellie May, a mother with type B blood, has a child with type o blood. She claims that Jethro, who has type A blood, is the father. He claims that he cannot possibly be the father. Further, blood tests ordered by the judge reveal that the father is homozygous. The judge rules that: a) Ellie May is right and Jethro must pay up. b) Jethro is right and is a winner winner (chicken dinner). c) Ellie May cannot be the real mother of the child. There must have been an error made at the hospital. d) It is impossible to reach a decision based on the limited data available. e) none of these are correct. 11. If a daughter expresses a sex-linked recessive gene, she inherited the trait from: a) her mother; b) her father, c) both parents; d) neither parents.

Please provide answes with punnet's squares

Answer 1

The woman is colour blind then her genotype will be XCXC

The man is normal so her genotype will be XY

	XC	XC
X	XCX	XCX
Y	XCY	XCY

So, all the daughters will be carriers and all the boys will be the sufferers.

A is incorrect as all will not be colour blind.

B is incorrect as all the daughters will not be colour blind.

C is correct as all the daughters will be carriers and all the boys will be the sufferers.

D is incorrect as all the daughters will be carriers.

E is incorrect as none of the daughters will be normal.

So, the correct answer is C.