ZuoTi.Pro
Question

A compound microscope has an overall length of 25cm. If the objective lens has a linear...

A compound microscope has an overall length of 25cm. If the objective lens has a linear magnification of 20 and the eyepiece has an apparent magnification of 10, what are their focal lengths? How close to the objective lens should be placed for viewing the final image? What is the total magnification?

science   physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Compound microccope Le Lu6 From problem tb mo2) 2) 12s Fe 2-5 cm

0 0
Add a comment
Know the answer?
Add Answer to:
A compound microscope has an overall length of 25cm. If the objective lens has a linear...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • A compound microscope has an objective lens of focal length 10.0 mm with an eyepiece of...

    A compound microscope has an objective lens of focal length 10.0 mm with an eyepiece of focal length 15.5 mm , and it produces its final image at infinity. The object to be viewed is placed 2.0 mm beyond the focal point of the objective lens. a. How far from the objective lens is the first image formed? b. What is the overall magnification of this microscope?

  • A compound microscope has an objective lens of focal length 10.5 mm with an eyepiece of...

    A compound microscope has an objective lens of focal length 10.5 mm with an eyepiece of focal length 15.4 mm, and it produces its final image at infinity. The object to be viewed is placed 2.0 mm beyond the focal point of the objective lens. Part A How far from the objective lens is the first image formed? Express your answer in millimeters to three significant figures. VO AZO ? 81 Imm Submit Request Answer Part B What is the...

  • The objective lens and the eyepiece of a microscope are 16.5 cm apart. The objective lens...

    The objective lens and the eyepiece of a microscope are 16.5 cm apart. The objective lens has a magnification of 61× and the eyepiece has a magnification of 10 ×. Assume that the image of the objective lies very close to the focal point of the eyepiece. A. Calculate the overall magnification of the microscope. B.Calculate the focal length of the eyepiece. C. Calculate the focal length of the objective.

  • The objective lens and the eyepiece of a microscope are 16.5 cm apart. The objective lens...

    The objective lens and the eyepiece of a microscope are 16.5 cm apart. The objective lens has a magnification of 61 × and the eyepiece has a magnification of 11 ×. Assume that the image of the objective lies very close to the focal point of the eyepiece. A) Calculate the overall magnification of the microscope. B) Calculate the focal length of the eyepiece. C) Calculate the focal length of the objective.

  • A compound microscope has an objective lens with a focal length of 0.40 cm and an...

    A compound microscope has an objective lens with a focal length of 0.40 cm and an ocular (eyepiece) with a focal length of 4.25 cm. The separation between the lenses is 20 cm. (a) Find the total magnification. (b) What focal length of the objective should be used to double the total magnification, if the focal length of the eyepiece and its separation from the objective remain the same?

  • A microscope has an objective lens with a focal length of 10.0 mm . A small...

    A microscope has an objective lens with a focal length of 10.0 mm . A small object is placed 0.90 mm beyond the focal point of the objective lens. If an eyepiece with a focal length of 2.5 cm is used, with a final image at infinity, what will be the overall angular magnification of the object? Express your answer using two significant figures.

  • Experiment 22: The Compound Microscope f2 Object 2 1 (Objective Lens)d L, (Eyepiece) d#150mm The Compound Microsco...

    Experiment 22: The Compound Microscope f2 Object 2 1 (Objective Lens)d L, (Eyepiece) d#150mm The Compound Microscope A compound microscope uses two lenses to provide greater magnification of near objects than is possible using a single lens as a magnifier. The setup is shown above. The objective lens, L1, functions as a projector. The object is placed just beyond the focal point of L1 so a real, magnified, inverted image is formed. The eyepiece, L2, functions as a magnifier. It...

  • A microscope has an objective lens with a focal length of 15.0 mm . A small...

    A microscope has an objective lens with a focal length of 15.0 mm . A small object is placed 0.90 mm beyond the focal point of the objective lens. Part A) At what distance from the objective lens does a real image of the object form? My answer: s' = 270 mm Part B) What is the magnification of the real image? My answer: m = -17 Part C) If an eyepiece with a focal length of 2.5 cm is...

  • The overall magnification of a compound microscope is |M|= 270. The distance between the eyepiece (f...

    The overall magnification of a compound microscope is |M|= 270. The distance between the eyepiece (f = 5 cm) and objective lens is 19 cm. What is the focal length of the objective lens and how far from the lens should the object be placed for the image to be in focus?

  • A. How far from the objective lens is the first image formed? B. What is the...

    A. How far from the objective lens is the first image formed? B. What is the overall magnification of this microscope? A compound microscope has an objective lens of focal length 9.70 mm with an eyepiece of focal length 15.5 mm, and it produces its final image at infinity. The object to be viewed is placed 2.0 mm beyond the focal point of the objective lens

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT