Question

Topic 4: Thévenin and Norton Exercise 4.2: Thévenin and Norton Equivalent Circuits 1 Find the Thévenin and Norton equivalents (between terminals A and B) of the circuit shown below. Try command executed. The exact answers are displayed next to your entries. Your score: 23 (Fail). Your score is not recorded for assessment purposes. New Problem Help Try View Submission Topic Menu Equation Solver "O: 8 R3 R1 - A(+) Your solution: True solution: 40 37 11 R4 R2 29 VTH = 1 V 2.900000E+00 V 1 RTH Ω 9.666667E-01 22 OB-) IN = 1 A 3.000000E+00 A © PMCL Version 2.0.0

Need to find Vth Rth and In, answers are on the right, thanks

Answer 1

Answer ) calculation of Van- 80 V2 V3 + (2) 3733 400 5A Sir With 29 analysis at rode Applyi Supernode lying 0 and ③ Vi tvi-v2 Vz-V2 t + V3 =0 yo 37 29 1.025 V, -0.052027 V2 +0.061509V2 =0 As uz vi 8 2 Applying nodal analysis at node ② - V2-vi + V2-V3 = - 5 40 37

-0.025 V + 0.052027 U2 -0.027V3=-5 (3 By solving eqn 0 , ① and ② Via -5.1 Vz -97.ou g Vz = 2.9 volt Vz volt Van 2-9 a so Uth= 2.9 x 10 [ so volt = 2.9 E400 Volt 2 ) Calculation of Roth

by short circuit and Deactivating Voltage source current source by open circuit- dummay nu 402 378 sin 291 7 Ran Rth= 29x = 0.96 662 29+1 OR Ran= 9.666X16 R] 3) INF Uth Rih INS 2.9 0.9686 In=3 Amp