10) The pH of a solution prepared by dissolving 0.550 mol of solid methylamine hydrochloride (CH3NH3Cl)...

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Answer 1

Answer #1

10) gives - CH3 NH3 Cl = 0.550 moles volume of solution = 1L so Concentration of CH3 NH3 U = 0.5som Concentration of cng Nug

Answer 2

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