Molar mass of CH4,
MM = 1*MM(C) + 4*MM(H)
= 1*12.01 + 4*1.008
= 16.042 g/mol
mass(CH4)= 35.2 g
use:
number of mol of CH4,
n = mass of CH4/molar mass of CH4
=(35.2 g)/(16.04 g/mol)
= 2.194 mol
Given:
P = 1.0 atm
n = 2.1942 mol
T = 25.0 oC
= (25.0+273) K
= 298 K
use:
P * V = n*R*T
1 atm * V = 2.1942 mol* 0.08206 atm.L/mol.K * 298 K
V = 53.6 L
Answer: C
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