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ΓαιιΗ An inverting-summing amplifier in (Figure 1) is ideal and Vo = -(802 +505 + 12vc). Suppose that Vcc = 11 V. Find the vathanks. both part a and b

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zoka Avec 4 Des 29 Lal + > Apply Virtual ground concept V(+)EVE)= OV Apply KCl at rode A ona -V C+0-Vo Rc Given 6- - Cerere 0a PART-A:_ e Ra, RG, Rc=15K , 24k, lok a (7) Ra, Rb, RC = 15000 24000 10000 PART-B: Given Va=ru, Ve=1 v=-(eva +54b+ izvc] - Nb = 11+8(2) +12(-1) = -3 v Vo=Vcc=-1v Ubonax=-11+8(2) +12(-) = 1.4 -5 PART-Bi T Vbnin, Abrax=-3, 1.4

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