Question

ow cuma mi Write a program that defines a 2D boolean ve indices of the array i& represent people. The l friends and false (0) otherwise. Impleme functions printArray () and commenttienda (). 10 1 2 3 means "friends") 3!. . void printeray(bool friends (115). Int routine) print array content as in the screenshot below. bool como Friends (bool friends1115). Int Towe, int i, int ). Inte): return true if the two people i andj have a common friend. k is the index of the common friends const int rowSize = 5; const int colSize = 5; bool friends [rowSizecolSize) { , 1, 0, 1, 1, 1, 0, 1, 0, 1, orico 1, 1, 0, 1, 2 Note: Use nested for loops. inly need to provide a copy of your code. No need for screenshot.

Answer 1

#include <iostream>
using namespace std;
void printArray(bool friends[][5],int rowSize)
{   
// initially print # |
cout<<"# | ";
for (int i=0;i<5;i++)
// then numbering
cout<<i<<" ";
// then line change
cout<<endl;
cout<<"-----------------"<<endl;
for(int i=0;i<rowSize;i++)
{   
// every row start with i |
cout<<i<<" | ";
for(int j=0;j<5;j++)
{ // if i,j is friend then print * otherwise space
if(friends[i][j]==1)
cout<<"* ";
else
cout<<" ";
  
}
cout<<endl;
}
}
bool commonFriends(bool friends[][5],int rowSize,int i,int j,int &k)
{
for(int col=0;col<5;col++)
{   
// check if both i,j have value 1 at same column if yes then it is common friend
if(friends[i][col]==1 && friends[j][col]==1)
{
k=col;
return 1;
}
}

this is working code if you have some difficulty so i am providing screenshot of my code

1 include <iostream> 2 using namespace std; 3 void printArray (bool friends [][5], int rowSize) 4 { // initially print # | cout<<"# "; for (int i=0;i<5;i++) // then numbering cout<<i<<" "; // then line change cout<<endl; cout<<"------- ----------"<<endl; for(int i=0;i<rowSize; i++) // every row start with il cout<<i<<" | "; for(int j=0; j<5; j++) { // if i,j is friend then print * otherwise space if(friends[i][j]==1) cout<<"*"; else cout<<" "; cout<<endl; 32 bool commonFriends (bool friends [][5], int rowSize, int i, int j, int &k) 33- { 34 for(int col=0;col<5;col++) 35 // check if both i, j have value 1 at same column if yes then it is common friend if(friends[i][col]==1 && friends [j][col]==1)

cout<<endl; 31 32 bool commonFriends (bool friends [][5], int rowSize, int i, int j, int &k) 33- { 34 for(int col=0;col<5;col++) 35 // check if both i,j have value 1 at same column if yes then it is common friend if(friends[i][col]==1 && friends [j][col]==1) k=col; return 1; return @; 51 - int main() { 52 const int rowSize =5; const int colSize =5; //declaration of matrix bool friends [rowSize][colSize]={ 0,1,0,1,1, 1,0,1,0,1, 0,1,0,0,0, 1,0,0,0,1,

54 51. int main() { const int rowSize =5; 53 const int colSize =5; //declaration of matrix 55 bool friends[rowSize][colSize]={ 0,1,0,1,1, 1,0,1,0,1, 0,1,0,0,0, 1,0,0,0,1, 1,1,0,1,0 printArray(friends, rowSize); int i, j, k=-1; cout<<"enter two people"<<endl; cin>>i>>j; commonFriends (friends, rowSize,i,j,k); if(k==-1) cout<<"there is no common friends"<<endl; else cout<< "there is common friends between " «<i<<" and " <<j«<" is "<< k<<endl; return 0;
output is

Output: # 1 0 1 2 3 4 ------ 1 * * 2. * 3 | * 4 * * * enter two people there is common friends between 4 and 3 is o