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Resistors R1 = 1.2 kΩ and R2 = 6.8 kΩ are connected in series with a...

Resistors R1 = 1.2 kΩ and R2 = 6.8 kΩ are connected in series with a 1.5 V cell in a single circuit loop. Find (a) the current through R1, (b) the voltage across R1, (c) the wattage of the resistor that dissipates the most energy.

Answers: (a. 0.19 mA, b. 0.23 V, c. 0.24 mW (R2))

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Answer #1

R=1.262 R2=6.8ke Total Resistance R=RTR2 R= 1:2+6.8 I=8ka V=1.5 V (a) Total cussent TEV- R 8X1022 -3 A 0.19 X 10 I= 0.1875 X1

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