Question

A 1.40 kΩ resistor is connected in series with a 0.800 kΩ resistor. This pair of resistors is connected in parallel with a 7.00 kΩ resistor. That combination is then connected in series with a 0.700 kΩ resistor and a 9.0-V ideal battery (no internal resistance of course).

A) sketch this circuit

B) Determine the total equivalent resistance of this circuit's arrangement

C) Determine the amount of current that flows through the battery

D) Determine the voltage drop across the 1.40 kΩ resistor.

Answer 1

0.7K2= =Rq I A او {7 K2=R & Hoke=R, a gookon = R2 D Rs = R + R2 = 1.4 kn +0.8kr 2.2k2 Now Rey کے PA + Rs* R3 Rst Ro 2.2 x 7. Rey = 0.7K et 2.2+7 Reg = 2.28 ka Corrent W = FR = I I= v through battery exitio : 29.94 MA llow from Kirchoff-low & ( Resistors in kr so Crosent in MA 9-0.73 - 7(1-5,) = o grob, (1.4 +0.8) F = 761-7) 8 2.25 = 7 I 7. II g 0.7 I-77 It 7 I = 0 9.211 = 7 I g- 7.7 I + 7 I = 0 I Shop 9.2 7 T I=1.312 9- 7.2 X 1.313, +757 0 2.432 I = Current through I = 3.7 1.9kr Am