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*Answer to first part is 6.0 Volts

4*1.5V= 6

4 AA cells are connected in series. These make a true battery of 49 volts. This voltage is then connected to three resistors. R1-200 Ω R2-200 Ω R3-800 Ω R1 and R2 are wired in series with each other, and that series combination is wired in parallel with R3 Start by drawing a schematic diagram of the circuit, then proceed to the calculations. Give all answers to 2 sigfigs precision. The combined resistance of the three resistors is 4 what is the current flowing through the 200Ω resistor? what is the current flowing through the 200Ω resistor? What is the current flowing through the 80002 resistor4 what is the voltage drop across the 200Ω resistor? What is the voltage drop across the 20002 resistor 492 What is the voltage drop across the 8002 resistor?40

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*Answer to first part is 6.0 Volts 4*1.5V= 6 4 AA cells are connected in series....
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